Re: e^x - (e^x*1i)^-1i - (e^pi)*sin( x + [pi/2] ) ... - PTC Community
e^(iπ) in 3.14 minutes, using dynamics | DE5 - YouTube
functional analysis - Show that the exponentials $1, e^{2\pi ix}, \dots , e ^{2\pi ikx}, \dots$ form the basis for trigonometric polynomials. - Mathematics Stack Exchange