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Abnormální prohlížeč Přísný a 2 b 2 c 2 ab bc ac Nerv Patois Tom Audreath

If a^2 + b^2 + c^2 - ab - bc - ca = 0 , prove that a = b = c .
If a^2 + b^2 + c^2 - ab - bc - ca = 0 , prove that a = b = c .

If a+b+c=12, ab+bc+ac=47, what is the meaning of a^2+b^2+c^2? : r/askmath
If a+b+c=12, ab+bc+ac=47, what is the meaning of a^2+b^2+c^2? : r/askmath

How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all  values of [math] a, b,[/math] and [math]c - Quora
How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all values of [math] a, b,[/math] and [math]c - Quora

Find the value of a+b+c, if a2 +b2 +c2 = 45 and ab + bc+ac=2.​ - Brainly.in
Find the value of a+b+c, if a2 +b2 +c2 = 45 and ab + bc+ac=2.​ - Brainly.in

if the roots of the equation a(b c)x^2+b(c a)x+c(a b)=0 are equal and a,b,c>0,  then prove that 2/b=1/a+1/c, i.e., a,b,c are in H.P.
if the roots of the equation a(b c)x^2+b(c a)x+c(a b)=0 are equal and a,b,c>0, then prove that 2/b=1/a+1/c, i.e., a,b,c are in H.P.

Can a2+b2+c2-ab-bc-CA be negative for some real value of a, b, and c? How &  why? - Quora
Can a2+b2+c2-ab-bc-CA be negative for some real value of a, b, and c? How & why? - Quora

a+b+c=12 and a2+b2+c2=50 find ab+bc+ca - Brainly.in
a+b+c=12 and a2+b2+c2=50 find ab+bc+ca - Brainly.in

Prove the following identities –|(-bc,b^2+bc,c^2+bc)(a^2+ac,-ac,c^2+ac)(a^2+ ab,b^2+ab,-ab)| = (ab + bc + ca)^3 ​ - Sarthaks eConnect | Largest Online  Education Community
Prove the following identities –|(-bc,b^2+bc,c^2+bc)(a^2+ac,-ac,c^2+ac)(a^2+ ab,b^2+ab,-ab)| = (ab + bc + ca)^3 ​ - Sarthaks eConnect | Largest Online Education Community

ab + bc + ca does not exceed aa + bb + cc
ab + bc + ca does not exceed aa + bb + cc

Solved Let a, b and c be integers Prove the following: | Chegg.com
Solved Let a, b and c be integers Prove the following: | Chegg.com

The determinant |{:(b^2-ab, b-c, bc-ac), (a b-a^2, a-b, b^2-ab) ,(b c-c a,  c-a, a b-a^2):}| equals (a)a b c\ (b-c)(c-a)(a-b) (b) (b-c)(c-a)(a-b) (c) (a +b+c)(b-c)(c-a)(a-b) (d) none of these
The determinant |{:(b^2-ab, b-c, bc-ac), (a b-a^2, a-b, b^2-ab) ,(b c-c a, c-a, a b-a^2):}| equals (a)a b c\ (b-c)(c-a)(a-b) (b) (b-c)(c-a)(a-b) (c) (a +b+c)(b-c)(c-a)(a-b) (d) none of these

a-b)^3 + (b-c)^3 + (c-a)^3=?` (a)`(a+b+c)(a^2+b^2+c^2-ab-bc-ac)` (b)`3(a-b)( b-c)(c-a)` (c)`( - YouTube
a-b)^3 + (b-c)^3 + (c-a)^3=?` (a)`(a+b+c)(a^2+b^2+c^2-ab-bc-ac)` (b)`3(a-b)( b-c)(c-a)` (c)`( - YouTube

If a^2 + b^2 + c^2 = 90 & a + b + c = 20 . Find the value of ab + bc + ca .
If a^2 + b^2 + c^2 = 90 & a + b + c = 20 . Find the value of ab + bc + ca .

Prove the following identities – |(b^2+c^2,ab,ac)(ba,c^2+a^2,bc)(ca,cb,a^2+b ^2)| = 4a^2b^2c^2 ​ - Sarthaks eConnect | Largest Online Education Community
Prove the following identities – |(b^2+c^2,ab,ac)(ba,c^2+a^2,bc)(ca,cb,a^2+b ^2)| = 4a^2b^2c^2 ​ - Sarthaks eConnect | Largest Online Education Community

If ( a + b + c ) = 15 and ( ac + bc + ca ) = 74 , find the value of (a^2+b^2 +c^2)
If ( a + b + c ) = 15 and ( ac + bc + ca ) = 74 , find the value of (a^2+b^2 +c^2)

Solved please be able to follow the comment: prove that for | Chegg.com
Solved please be able to follow the comment: prove that for | Chegg.com

Resolve into linear factors `a^2+b^2+c^2-ab-bc-ca` - YouTube
Resolve into linear factors `a^2+b^2+c^2-ab-bc-ca` - YouTube

How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all  values of [math] a, b,[/math] and [math]c - Quora
How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all values of [math] a, b,[/math] and [math]c - Quora

radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge  ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange
radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange

Using properties of determinants, prove that `|[a^2, bc, ac+c^2] , [a^2+ab,  b^2, ac] , [ab, b^2+bc, - YouTube
Using properties of determinants, prove that `|[a^2, bc, ac+c^2] , [a^2+ab, b^2, ac] , [ab, b^2+bc, - YouTube

If a^2+b^2+c^2=16 and a b+b c+c a=10 , find the value of a+b+c
If a^2+b^2+c^2=16 and a b+b c+c a=10 , find the value of a+b+c

Prove that a2 + b2 + c2 - ab - ac - bc is always non-negative.  Polynomials-Maths-Class-9
Prove that a2 + b2 + c2 - ab - ac - bc is always non-negative. Polynomials-Maths-Class-9

If a = 2012, b = 2011, c =2010 then the value of a^2 + b^2 + c^2- ab- bc -  ca is? - Quora
If a = 2012, b = 2011, c =2010 then the value of a^2 + b^2 + c^2- ab- bc - ca is? - Quora

matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2  )$ - Mathematics Stack Exchange
matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange

CBSE Class 9 Answered
CBSE Class 9 Answered

If a^2 + b^2 + c^2 - ab - bc - ca = 0 , prove that a = b = c .
If a^2 + b^2 + c^2 - ab - bc - ca = 0 , prove that a = b = c .